Help!

[Zherwty]

I need help solving this logarithic function!

If Logx (1 / 8) = - 3 / 2, then x is equal to

A. - 4
B. 4
C. 1 / 4
D. 10

I started out by taking 10^(logx(1/8))=10^(-3/2) but then what should I do next?

[Doc Oc]

First, the logarithmic function is of base x so inorder to cancel it out you need to take x to that power. So x^[logx(1/8)] = (1/8) = x^(-3/2). Now you need to isolate x so take x^(-3/2) up to the (-2/3) power so [x^(-3/2)]^(-2/3).

Now since we know that (x^a)^b = x^(a*b) that means that x is now to the power -3/2*-2/3 which is 1. So now that we have x^1 = x we know the answer is 1/8^(-2/3) = ?? You should be able to do the rest

[Ocalon]

'nough said! Great job on the explanation.